Solving a quadratic equation by completing the square

steve · Joined: 05 Nov 2006 Posts: 13

Here's the equation 2x^2-2x+7=0 My 89 keeps telling me false as the answer. I'm trying to use the solve program with a , x after the 0 then closing the brackets. That's not working. Any suggestions?

rockvee · Joined: 24 Sep 2006 Posts: 45 Location: London, Ontario

you need solve() function to solve equation. Either type it or it's under algebra menu. It should be solve(2x^2-2x+7=0,x).

I am not sure what you mean by "completing the square"....the calculator just solve it....

baseballdude_ · Joined: 20 Sep 2006 Posts: 76 Location: Wisconsin

bostonvaulter · Joined: 13 Oct 2006 Posts: 43 Location: USA

I believe that it's giving false because there are no answers in the real number set. This is because when you use the quadratic equation, the term that goes under the square root, b^2-4ac is negative.

rockvee · Joined: 24 Sep 2006 Posts: 45 Location: London, Ontario