| Author |
Message |
steve
Joined: 05 Nov 2006
Posts: 13
|
 Posted: November 5, 2006 11:13 AM Post subject: Cube roots and greater with the TI-89 |
 |
|
I was given a TI-89 by my neighbor, but without the manual. I've ordered the dummies book, but I'm working with the calculator while awaiting delivery. My question is how do I work a root problem that is a cube root or greater?For example: the 5th root of 32z^12= 2z^2*5th root of z^2
Can this problem be done, and how if the answer is yes. I'd appreciate the help because this one really has me stumped. Thanks |
|
| Back to top |
|
 |
baseballdude_
Joined: 20 Sep 2006
Posts: 76
Location: Wisconsin
|
| Posted: November 5, 2006 12:23 PM Post subject: Re: Cube roots and greater with the TI-89 |
|
|
| steve wrote: | I was given a TI-89 by my neighbor, but without the manual. I've ordered the dummies book, but I'm working with the calculator while awaiting delivery. My question is how do I work a root problem that is a cube root or greater?For example: the 5th root of 32z^12= 2z^2*5th root of z^2
Can this problem be done, and how if the answer is yes. I'd appreciate the help because this one really has me stumped. Thanks |
Any root can be done with the root() function. You can type in the function, or press [Diamond] + [9]
There are two arguments - the first is the expression, the second is the number of the root.
So to take the 5th root of z squared, you can type in:
root(z^2,5) |
|
| Back to top |
|
|
bostonvaulter
Joined: 13 Oct 2006
Posts: 43
Location: USA
|
| Posted: November 5, 2006 12:59 PM Post subject: |
|
|
hmmm, the [diamond] + [9] thing doesn't work for me. Also i don't see the function root() under [catalog].
An easier way to do it would be with exponents. for example to find the 5th root of z, just type z^(1/5) |
|
| Back to top |
|
|
rockvee
Joined: 24 Sep 2006
Posts: 45
Location: London, Ontario
|
| Posted: November 5, 2006 3:45 PM Post subject: |
|
|
| bostonvaulter wrote: | hmmm, the [diamond] + [9] thing doesn't work for me. Also i don't see the function root() under [catalog].
An easier way to do it would be with exponents. for example to find the 5th root of z, just type z^(1/5) |
well, type "root()" should work |
|
| Back to top |
|
|
bostonvaulter
Joined: 13 Oct 2006
Posts: 43
Location: USA
|
| Posted: November 5, 2006 5:49 PM Post subject: |
|
|
| rockvee wrote: | | well, type "root()" should work |
doesn't work for me. Maybe it's because I have a plain 89? |
|
| Back to top |
|
|
steve
Joined: 05 Nov 2006
Posts: 13
|
| Posted: November 5, 2006 6:00 PM Post subject: |
|
|
| Doesn't work for me , I have a plain old 89 also. I've figured out how to do roots using exponents as stated above. my problem is when I have something like this: cube root of 54x^4 I solve this out to 3x*cube root of 2x. I have no idea how to do something like this. Any suggestions? |
|
| Back to top |
|
|
bostonvaulter
Joined: 13 Oct 2006
Posts: 43
Location: USA
|
| Posted: November 5, 2006 8:02 PM Post subject: |
|
|
| Sorry, I don't understand your example... |
|
| Back to top |
|
|
steve
Joined: 05 Nov 2006
Posts: 13
|
| Posted: November 5, 2006 9:09 PM Post subject: |
|
|
| Okay you have 54x^4 all underneath a cube root. I solved this to be 3x*2x underneath a cube root. I know this is very basic algebra, but it's really giving me a hard time solving it.[/list] |
|
| Back to top |
|
|
bostonvaulter
Joined: 13 Oct 2006
Posts: 43
Location: USA
|
| Posted: November 5, 2006 11:18 PM Post subject: |
|
|
you should probably use parentheses.
so for your example you could just type in
(54x^4)^(1/3)
but unfortunately I don't think that there is an easy way to get your answer of
(3x*2x)^(1/3)
because I got
3*2^(1/3)*x^(4/3)
You can extrapolate your answer from that, but that is rather difficult. |
|
| Back to top |
|
|
|
