mellamokb
Joined: 10 May 2007
Posts: 124
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 Posted: May 17, 2007 10:32 PM Post subject: |
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Hi dan96z28,
You can find a solution for b1 if you don't use "floor(". It is impossible for the calculator to return the solution because there are an infinite number of values that b1 can take on.
If you are wanting the range of values that b1 can take on and still equal 12500 after the floor function is applied, I would suggest using these two equations:
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solve(1.92863*b1=12500,b1)
solve(1.92863*b1=12501,b1)
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The first entry will result in the smallest value that b1 can take on in your original equation. The second entry will result in the largest value that b1 can take on in your original equation.
Hope this helps!
~ mellamokb |
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