simon.gansen
Joined: 13 Aug 2008
Posts: 1
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 Posted: August 13, 2008 8:19 AM Post subject: Fourier Analysis |
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Hi,
for my next exam I need to be able to perfom Fourier. All Functions of the TI-89 Titanium are allowed in case we reset memory. I want to calculate the following expression:
ak= 2/T * int{u(t)*cos(k*omega*t),t,0,1s}
T=1s; u(t)= (1V/1s) * t; omega=2*PI*f=2PI/T
Because u(t) is an odd sawtooth function, the cos-Compontent should be 0. My TI told me some other stuff. Maybe it doesn't "knows" that sin(k2PI)=0 (k=0,1,2...inf). Is there any possibility without adding new software?
Thanks!
Simon[/code] |
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